Consider a hydrogen like atom whose energy in nth excited state is given by En=−13.6Z2n2 when this excited atom makes a transition from excited state to ground state, most energetic photons have energy Emax=52.2224eV and least energetic photons have energy Emin=1.224eV. What is the atomic number of atom?

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answer is 2.

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Detailed Solution

Maximum energy is liberated for transition En→E1 and minimum energy for En→En−1 Hence E1n2−E1=52.224eV and E1n2−E1(n−1)2=1.224eV ⇒ E1=−54.4eV and n=5 Now E1=−13.6Z212=−54.4eV. Hence Z=2

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