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Q.

Consider a hydrogen-like ion .The maximum energy of a photon in Lymann series emitted by this ion is 54.4 ev .Then what will be the energy of a photon in the first line of Balmer series ?

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a

7.55 ev

b

5.16 ev

c

4.75 ev

d

None of these

answer is A.

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Detailed Solution

13.6 z2 ( 1-1∞ ) =54.4   ⇒ z =2  Therefore , energy of photon in the first line of Balmer series                         = 13.6 ×22( 122- 132) ev                  =7.55ev
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