P-N junction diode

Question

Consider the junction diode as ideal. The value of current flowing through A B is

Easy

Solution

Here, the p-n junction diode is forward biased, hence it offers zero resistance.

$\therefore {I}_{AB}=\frac{{V}_{A}-{V}_{B}}{{R}_{AB}}=\frac{4\mathrm{V}-(-6\mathrm{V})}{1\mathrm{k}\Omega}=\frac{10}{1000}\mathrm{A}={10}^{-2}\mathrm{A}$

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