Questions
Consider an n-p-n transistor amplifier in common-emitter configuration. The current gain of the transistor is 100. If the collector current changes by 1 mA, what will be the change in emitter current?
detailed solution
Correct option is A
Current gain =Change in collector currentChange in base currentβ=ΔiCΔiBAlso iE=iB+iC⇒ΔiE=ΔiB+ΔiCβ=ΔiCΔiE−ΔiCGiven, β=100, ΔiC=1 mA∴100=1ΔiE−1 ΔiE−1=1100=0.01ΔiE=1+0.01=1.01 mATalk to our academic expert!
Similar Questions
In a common-base mode of transistor, the collector current is 5 488 mA for an emitter current of 5 .60 mA. The value of the base current amplification factor (p) will be
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
