Consider an n-p-n transistor amplifier in common-emitter configuration. The current gain of the transistor is 100. If the collector current changes by 1 mA, what will be the change in emitter current?
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a
1.01 mA
b
1.1 mA
c
0.01 mA
d
10 mA
answer is A.
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Detailed Solution
Current gain =Change in collector currentChange in base currentβ=ΔiCΔiBAlso iE=iB+iC⇒ΔiE=ΔiB+ΔiCβ=ΔiCΔiE−ΔiCGiven, β=100, ΔiC=1 mA∴100=1ΔiE−1 ΔiE−1=1100=0.01ΔiE=1+0.01=1.01 mA