Consider an NPN transistor amplifier in common-emitter configuration. The current gain of the transistor is 100. If the collector current changes by 1 mA, what will be the change in emitter current(in mA)
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a
1.1
b
1.01
c
0.01
d
10
answer is B.
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Detailed Solution
Current gain,β=ΔicΔib⇒Δib=1×10−3100=10−5A=0.01mA .By using Δie=Δib+Δic⇒Δie=0.01+1=1.01 mA .