Q.

Consider an optical communication system operating at λ=600nm. Suppose, only 1% of the optical source frequency is the available channel bandwidth for optical communication. Number of channels that can be accommodated for transmitting audio signals requiring a bandwidth of 8kHz are _____ ×108

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answer is 0006.25.

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Detailed Solution

Optical source frequency  f=cλ=3×108/(600×10−9)=5×1014Hz Bandwidth of channel  (1% of above) =1%of 5×1014=1100×5×1014=5×1012HzNumber of channels = (Total bandwidth of channel)/ (Bandwidth needed per channel) So, Number of channels for audio signal=(5×1012)/(8×103)=6.25×108
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