Consider parallel conducting rails separated by a distance l. There exists a uniform magnetic field B perpendicular to the plane of the rails as shown in figure. Two conducting wires each of length l are placed so as to slide on parallel conducting rails. One of the wires is given a velocity $$v0$$ parallel to the rails. Till steady state is achieved, loss in kinetic energy of the system is

Question

Consider parallel conducting rails separated by a distance l. There exists a uniform magnetic field B perpendicular to the plane of the rails as shown in figure. Two conducting wires each of length l are placed so as to slide on parallel conducting rails. One of the wires is given a velocity $$v0$$ parallel to the rails. Till steady state is achieved, loss in kinetic energy of the system is

Infinity Learn · Accepted Answer

In steady state, velocity of both wires will become $$same.2mv=mv0$$⇒$$v=v0/2Loss$$ in $$KE$$ $$=12mv02-212mv2=14mv02$$

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