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Consider parallel conducting rails separated by a distance l. There exists a uniform magnetic field B perpendicular to the plane of the rails as shown in figure. Two conducting wires each of length l are placed so as to slide on parallel conducting rails. One of the wires is given a velocity v0 parallel to the rails. Till steady state is achieved, loss in kinetic energy of the system is

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detailed solution

Correct option is C

In steady state, velocity of both wires will become same.2mv=mv0⇒v=v0/2Loss in KE =12mv02-212mv2=14mv02

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