Consider $$3rd$$ orbit of $$He+$$ (Helium), using $$non-relativistic$$ approach, the speed of electron in this orbit will be [given $$K=9x109$$ constant, Z $$=$$ $$2$$ and h (Planck$$'s $$Constant) $$=6.6$$×$$10-34$$ J s

Question

Consider $$3rd$$ orbit of $$He+$$ (Helium), using $$non-relativistic$$ approach, the speed of electron in this orbit will be [given $$K=9x109$$ constant,  Z $$=$$ $$2$$ and h (Planck$$'s $$Constant) $$=6.6$$×$$10-34$$ J s

Infinity Learn · Accepted Answer

Energy of electron in $$He+$$ $$3rd$$ orbit $$E3=-13.6$$×$$Z2n2eV=-13.6$$×$$49eV$$       $$=-13.6$$×$$49$$×$$1.6$$×$$10-19$$ J≃$$9.7$$×$$10-19$$ JAs per Bohr's model,Kinetic energy of electron in the $$3rd$$ orbit $$=$$ $$-$$ $$E3$$∴  $$9.7$$×$$10-19=12mev2v=2$$×$$9.7$$×$$10-199.1$$×$$10-31=1.46$$×$$106$$ m $$s-1$$

Consider 3rd orbit of ${He}^{+}$ (Helium), using non-relativistic approach, the speed of electron in this orbit will be $[given K = 9 x 10^{9}$ constant, Z = 2 and h (Planck's Constant) $= 6.6 \times 10^{- 34} J s]$

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Consider 3rd orbit of He+ (Helium), using non-relativistic approach, the speed of electron in this orbit will be [given K=9x109 constant, Z = 2 and h (Planck's Constant) =6.6×10-34 J s

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Consider 3rd orbit of ${He}^{+}$ (Helium), using non-relativistic approach, the speed of electron in this orbit will be $[given K = 9 x 10^{9}$ constant, Z = 2 and h (Planck's Constant) $= 6.6 \times 10^{- 34} J s]$