First slide
Law of conservation of angular momentum
Question

Consider a rod of mass M and length L pivoted at its centre is free to rotate in a vertical plane. The rod is at rest in the vertical position. A bullet of mass M moving horizontally at a speed v strikes and embedded in one end of the rod. The angular velocity of the rod just after the collision will be

Moderate
Solution

Apply conservation of angular momentum about the pivot point

0+MVL/2=Iω HERE I=ML212+ML22

  ω = 3v2L

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