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Consider the rods of same length and different specific heats (s₁,s₂), conductivities ( k₁ ,k₂ ) and areas of cross-sections ( A₁ ,A₂) and both having temperature T₁ and T₂ at their ends. If the rate of loss of heat due to conduction is equal, then:

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k1A1=k2A2

k1A1s1=k2A2s2

k2A1=k1A2

k1A1s2=k1A2s1

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detailed solution

Correct option is A

dQdt=kA(T1-T2)l=same so k1A1=k2A2

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Consider the rods of same length and different specific heats (s1,s2), conductivities ( k1 ,k2 ) and areas of cross-sections ( A1 ,A2) and both having temperature T1 and T2 at their ends. If the rate of loss of heat due to conduction is equal, then:

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Ready to Test Your Skills?

free study material

Consider the rods of same length and different specific heats (s₁,s₂), conductivities ( k₁ ,k₂ ) and areas of cross-sections ( A₁ ,A₂) and both having temperature T₁ and T₂ at their ends. If the rate of loss of heat due to conduction is equal, then: