Q.

Consider the rotation of a rod of mass m and length l from position AB to AB'. Which of the following statements are correct?

Moderate

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By Expert Faculty of Sri Chaitanya

Centre of gravity of the rod is lowered by l/2.

Loss of gravitational potential energy is l/2 mgl.

Angular velocity is 3g/l.

Rotational kinetic energy is ml2ω26

answer is 1,2,3,4.

(Detailed Solution Below)

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Detailed Solution

Equating loss of gravitational potential energy with the gain of rotational kinetic energy, we get12Iω2=12mgl12×ml23×ω2=12mglω=3glRotational kinetic energy =12ml23ω2=ml2ω26

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