Consider the situation shown in figure. Water (μ = 4/3) is filled in a beaker up to a height of 10 cm. A plane mirror is fixed at a height of 5 cm from the surface of water. Distance of image from the mirror after reflection from it of an object O at the bottom of the beaker is

Distance of first image (I1,) formed after refraction from the plane surface of water is 104/3=7.5 cm from water surface dapp=dactual μNow, distance of this image is 5 + 7.5 = 12.5 cm from the plane mirror. Therefore, distance of second image (I2) will also be equal to 12.5 cm from the mirror.