Consider the situation shown in figure. Water $$($$μ $$=$$ $$4/3)$$ is filled in a beaker up to a height of $$10$$ cm. A plane mirror is fixed at a height of $$5$$ cm from the surface of water. Distance of image from the mirror after reflection from it of an object O at the bottom of the beaker is

Question

Consider the situation shown in figure. Water $$($$μ $$=$$ $$4/3)$$ is filled in a beaker up to a height of $$10$$ cm. A plane mirror is fixed at a height of $$5$$ cm from the surface of water. Distance of image from the mirror after reflection from it of an object O at the bottom of the beaker is

Infinity Learn · Accepted Answer

Distance of first image (I1$$,$$) formed after refraction from the plane surface of water is $$104/3=7.5$$ cm from water surface $$dapp=dactual$$ μNow, distance of this image is $$5$$ $$+$$ $$7.5$$ $$=$$ $$12.5$$ cm from the plane mirror. Therefore, distance of second image (I2) will also be equal to $$12.5$$ cm from the mirror.

Consider the situation shown in figure. Water ( $μ$ = 4/3) is filled in a beaker up to a height of 10 cm. A plane mirror is fixed at a height of 5 cm from the surface of water. Distance of image from the mirror after reflection from it of an object O at the bottom of the beaker is

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Consider the situation shown in figure. Water (μ = 4/3) is filled in a beaker up to a height of 10 cm. A plane mirror is fixed at a height of 5 cm from the surface of water. Distance of image from the mirror after reflection from it of an object O at the bottom of the beaker is

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Consider the situation shown in figure. Water ( $μ$ = 4/3) is filled in a beaker up to a height of 10 cm. A plane mirror is fixed at a height of 5 cm from the surface of water. Distance of image from the mirror after reflection from it of an object O at the bottom of the beaker is