Consider the situation shown in figure. We find electric field E at point P using Gauss's law and it comes out to be E=σ/ε0. This electric field is due to
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a
all the amount of charges present on both the plates
b
all the charges present on positive plate only
c
positive charge present only inside the Gaussian surface
d
positive charge present inside the Gaussian surface plus equal magnitude of negative charge present on negative plate in front of Gaussian surface
answer is A.
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Detailed Solution
According to Gauss's law, electric field at any point on Gaussian surface is due to all the charges present inside or outside.