Consider a sphere of radius R which carries a uniform charge density ρ. If a sphere of radius R2 is carved out of it, as shown , the ratio E→AE→Bof magnitude of electric field E→Aand E→B . respectively, at points A and B due to the remaining portion is:

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

1834

1854

1754

2134

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Assume charge density inside cavity and outside cavity is +ρ and −ρ respectively.Ein=ρr3∈0 rRPoint A is inside both spheres, EA =E1+E2 = ρ3ε00+−ρ3ε0R2 = −ρR6ε0Point B inside for 1 and outside for 2EB =E1+E2 = ρR3ε0+−ρ3ε0R233R22=17ρR54ε0Ratio = EA EB =1834

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

Get Expert Academic Guidance – Connect with a Counselor Today!

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET