Consider a sphere of radius R which carries a uniform charge density 'ρ' . If a sphere of radius R2 is carved out of it, as shown. The ratio EAEB of magnitude of electric field E→A and E→B, respectively at points A and B due to the remaining portion is
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answer is 4.
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Detailed Solution
Consider the smaller sphere having negative charge density.EA=O+Kρ.43πR23R/22=Kρ43πR2 EB=Kρ43πR3R2−Kρ43πR233R22 =Kρ43πR−Kρ43πR18 =Kρ43π17R18 ∴EAEB=Kρ43πR/2Kρ43π17R18 EAEB=1834