consider a system of masses M₁ and M₂ (M₁ > M₂) connected by a massless string. In Figure (A), the system is pulled by a force F from the side of mass M₁ and in Figure (B), the system is pulled by the same force F from the side of mass M₂, then:

Easy

A

acceleration in the two cases is same and tension in the string connecting M₁ and M₂ is also same
B

acceleration of system in (A) is more than in (B) while tension in the string is same in both cases
C

acceleration of system in both cases is same but tension in the string in (A) is more than in (B)
D

acceleration of system in both cases is same but tension in the string in (A) is less than in (B)

Solution

In both cases, acceleration $a = \frac{F}{M_{1} + M_{2}}$
In (A), $T_{A} = M_{2} a = \frac{M_{2} F}{M_{1} + M_{2}}$
In(B), $T_{B} = M_{1} a = \frac{M_{1} F}{M_{1} + M_{2}}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

SCAN ME