Q.

Consider the system as shown in the figure. The pulley and the string are light and all the surfaces are frictionless. The tension in the string is (g: l0 m/s2)

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a

0 N

b

l N

c

2 N

d

5 N

answer is D.

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Detailed Solution

The acceleration of block of mass m1 isa = m1m1+m2g = 5 m/s2From FBD of block m1m1g -T = m1a⇒T = m1(g-a) = 1×5 = 5 N
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Consider the system as shown in the figure. The pulley and the string are light and all the surfaces are frictionless. The tension in the string is (g: l0 m/s2)