Consider a thin metallic sheet perpendicular to the plane of the paper moving with speed ‘v’ in a uniform magnetic field B going into the plane(see figure).If charge densities σ1 and σ2 are induced on the left and right surfaces, respectively, of the sheet then (ignore fringe effects):
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
σ1=−ε0vB2,σ2=ε0vB2
b
σ1=ε0vB, σ2=−ε0vB
c
σ1=ε0vB2, σ2=−ε0vB2
d
σ1=σ2=ε0vB
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
∵F=qE and F=qvB ∴E=vB And Gauss's law in Electrostatic E=σε0 E=σε0=vB⇒σ=ε0vB σ1=−σ2
Consider a thin metallic sheet perpendicular to the plane of the paper moving with speed ‘v’ in a uniform magnetic field B going into the plane(see figure).If charge densities σ1 and σ2 are induced on the left and right surfaces, respectively, of the sheet then (ignore fringe effects):