Consider the three cases given in figures shown. Assume the friction to be absent everywhere and the pulleys to be light; the string connecting the blocks to other block or flxed vertical wall to be light and inextensible . Let TA, TB and TC be the tension in the strings in figure A, figure B and figure C respectively. Then pick the correct comparison between the given tensions (for the instant shown) from options below.

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TA = TB = TC

TB = TC < TA

TA < TB < TC

TB < TC < TA

answer is B.

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Detailed Solution

TA =2kgf.TB=Total forcetotal mass×Horizontally moving mass=2(1+2)×1=23kgf.Similarly TC=1(2+1)×2=23kgf.Hence TB=TC