Consider three long, straight, parallel wires shown in fig. The force experienced by 25 cm length of wire C is

Force on 25 cm long wire C due to A isFCA=μ04π×2iA×iC3×10−2×25100 towards right =10−7×2×30×10×253N=5×10−4NForce on 25 cm long wire C due to B isFCB=μ04π×2iB×iC5×10−2×25100 towards left =10−7×2×10×20×255N=2×10−4NNet force F = (FCA - FCB) towards right= 3x 10-4 N towards right