Consider two charged metallic sphere S1 and S2 of radii R1 and R2, respectively. The electric fields E1(on S1) and E2(on S2) on their surfaces are such that E1/E2=R1/R2. Then the ratio V1on S1/V2on S2 of the electrostatic potentials on each sphere is :
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a
R2/R1
b
R1/R22
c
R1R23
d
R1/R2
answer is B.
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Detailed Solution
Given : E1E2=R1R2We know, E=kQR2 and V=kQR∴V=ER⇒V1V2=E1R1E2R2=R1R2×R1R2=R1R22