Consider two ideal diatomic gases A and B at some temperature T. Molecules of the gas A are rigid, and have a mass m. Molecular of the gas B has an additional vibrational mode, and have a mass m4 . The ratio of the specific heats (CVA and CVB ) of gas A and B , respectively is :
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a
5:9
b
5:7
c
3:5
d
7:9
answer is B.
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Detailed Solution
For Gas A (diatomic), degree of freedom (f) = 3+2 = 5 For Gas B (diatomic + vibration), degree of freedom (f) = 3+2 +2= 7In general, for any gas Specific heat at constant volume CV=fR2Specific heat at constant volume of A=52RTSpecific heat at constant volume of B=72RT ∴ Ratio=57