Consider two identical cells each of emf E and internal resistance r connected to a load resistance R.Now, match the given columns and select the correct option from the codes given below.

Question

Infinity Learn · Accepted Answer

If cells are connected in series: Eeq  $$=$$  $$2E$$,  req $$=$$ $$2r$$.Maximum power will be transferred if $$R=req$$  $$=2r$$.Then current in R:  $$I=EeqR+req$$  $$=$$  $$2E2r+2r$$ $$=E2rPower$$  $$=$$  $$I2$$ $$R=$$ $$E2r2$$  $$2r=E22rIf$$ cells are connected in parallel: Eeq  $$=$$  E,  req $$=$$ $$r2For$$ maximum power: $$R=req$$  $$=r2$$,  Then current in R:$$I=EeqR+req$$  $$=$$  $$Er2+r2$$ $$=ErPower$$ : $$I2R$$ $$=$$ $$Er2$$  $$r2$$ $$=$$  $$E22rHence$$ [i $$-$$ q] [ii $$-$$ q] [iii $$-$$ s] [iv $$-r$$]

Column I		Column II
i.	Maximum power transfer to load if cells are connected in series	p.	$\frac{E^{2}}{4 r}$
ii.	Maximum power transfer to load if cells are connected in parallel	q.	$\frac{E^{2}}{2 r}$
iii.	For series connection of cells	r.	$E_{eq} = E, r_{eq} = \frac{r}{2}$
iv.	For parallel connection of cells	s.	$E_{eq} = 2 E, r_{eq} = 2r$

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