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Consider two solid spheres of radii $R_{1} = 1 m, R_{2} = 2 m$ and masses $M_{1}$ and $M_{2}$ , respectively. The gravitational field due to sphere 1 and 2 are shown. The value of $\frac{M_{1}}{M_{2}}$
is :

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detailed solution

Correct option is C

At surface peak of the graph, g=GMR2For Sphere 2 field at surface is 3=GM222 −−−−1 For Sphere 1 field at surface is 2=GM112 −−−−2dividing 2 by 1 we get ∴32=GM24GM1 ∴32=M24M1 ⇒ M1M2=16

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Consider two solid spheres of radii R1=1m,R2=2m and masses M1 and M2, respectively. The gravitational field due to sphere 1 and 2 are shown. The value of M1M2 is :

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Consider two solid spheres of radii $R_{1} = 1 m, R_{2} = 2 m$ and masses $M_{1}$ and $M_{2}$ , respectively. The gravitational field due to sphere 1 and 2 are shown. The value of $\frac{M_{1}}{M_{2}}$
is :