First slide

Electric Flux

Question

Consider a uniform electric field $E == 3 \times 10^{3} \overset{⏜}{i} N / C$ . What is the flux of this field through a square of 10 cm on a side whose plane is parallel to the yz-plane?

Moderate

A

$30 {Nm}^{2} / C$
B

$40 {Nm}^{2} / C$
C

$50 {Nm}^{2} / C$
D

$60 {Nm}^{2} / C$

Solution

Given that the electric field intensity is (3 x10³)hence, the magnitude of electric field intensity is $| \vec{E} | = 3 \times 10^{3} N / C)$ , the side of the square is s=10cm=0.1m; area of the square is A=S²=0.01m² The plane of the square is parallel to the y-z plane; therefore, the angle between the unit vector normal to the plane and electric field is given by $θ$ = 0^o. Now, the flux through the plane is given by
$ϕ = | \vec{E} | Acos θ$ ……………….(1)
Substituting the values in Eq. (1), we get
$ϕ = 3 \times 10^{3} \times 0.01 \times \cos 0^{\circ} = 30 {Nm}^{2} / C$ .

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