Consider a uniform wire of mass M and length L. It is bent into a semicircle. Its moment of inertia about a line perpendicular to the plane of the wire passing through the centre is:
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a
ML2π2
b
14ML2π2
c
12ML2π2
d
25ML2π2
answer is A.
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Detailed Solution
Since all element of wire are same distance from axis, moment of Inertia is I=Mr2 Where r=Lπ is radius of semicircle I=MLπ2 ⇒I=ML2π2