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An Intiative by Sri Chaitanya
a
E→ must be the electric field due to the enclosed charge
b
If net charge inside the Gaussian surface =0, then E→ must be zero everywhere over the Gaussian surface.
c
If the only charge inside the Gaussian surface is an electric dipole, then the integral is zero.
d
E→ is parallel to dA→ everywhere over the Gaussian surface.
answer is C.
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