Questions
A constant force F = m2 g / 2 is applied on the block of mass m, as shown in fig. The string and the pulley
are light and the surface of the table is smooth The acceleration of m1 is
detailed solution
Correct option is A
Let a be the acceleration of mass m2 in the downward direction. Then T -m2(g/2) = m1a …(1)and m2 g -T = m2 a …(2)Adding eqs. (1) and (2), we getm1+m2a=m2g−m2(g/2)=m2g/2∴ a=m2g2m1+m2.Talk to our academic expert!
Similar Questions
A constant force F = m2g/2 is applied on the block of mass m1 as shown. The string and the pulley are light and the surface of the table is smooth. Find the acceleration of m1.
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