First slide
Dynamics of rotational motion about fixed axis
Question

A constant torque of 1000 Nm turns a wheel of of M.I 200kg m2 about an axis through centre. The angular velocity after 3s is

Easy
Solution

ω0 = 0
\large \tau = I\alpha \Rightarrow \alpha = \frac{\tau }{I} = \frac{{1000}}{{200}} = 5rad/{s^2}
at t = 3sec
\large \omega = \omega_0+\alpha(t)=0+5(3)=15rad/s

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