Questions
A constant torque of 1000 N-m turns a wheel of moment of inertia 200 kg-m2 about an axis through its centre. Its angular velocity after 3 s is
detailed solution
Correct option is D
Angular acceleration, α=τI=1000200=5rads-2Now, angular velocity, ω=αt=(5)(3)=15rads-1Talk to our academic expert!
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The instantaneous angular position of a point on a rotating wheel is given by the equation (t) = 2t3 6t2. The torque on the wheel becomes zero at [CBSE AIPMT 2011]
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