First slide
Fluid dynamics
Question

A container having a hole at the bottom is free to move on a horizontal surface. As the liquid comes out, the container with an acceleration α and finally acquires a velocity v ( when the liquid has drained out). Neglect the mass of container. The correct option out of the following is:
 

Easy
Solution

The reaction of out flowing liquid
= mass coming out per sec x velocity of container
     (Ahρ)α=ρau.υ=ρa.2gh
with a and A as area of hole and container
                           α=2agA

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