A container of large cross-sectional area has a small orifice at its bottom. The container is filled with water upto a height of ‘h’ above the orifice and mass flow rate of water through the orifice is 2 Kg/sec. If the height of water surface above the orifice is made 4h and cross-sectional area of the orifice is doubled, then mass flow rate of water will be
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a
12 Kg
b
16 Kg
c
4 Kg
d
8 Kg
answer is D.
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Detailed Solution
If ‘a’ be the cross sectional area of the orifice, then mass flow rate m=ρ.a.2gh∴ m•1m•=a1ah1h⇒m•12=24⇒m•1=8 Kg