A converging beam of rays is incident on a diverging lens. Having passed through the lens the rays intersect at a point 15 cm from the lens. If the lens is removed the point where the rays meet will move 5 cm closer to the mounting that holds the lens. Find focal length (in cm ) of the lens.
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answer is -30.00.
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Detailed Solution
For concave lens, u=+10cm (virtual object) and v=+15cm We have 1+15−1+10=1f ∴ f=−30cm.