First slide

Moving coil Galvanometer

Question

To convert a 800 mV range milli voltmeter of resistance $40 Ω$ into a galvanometer of 100 mA range, the resistance to be connected as shunt is

Moderate

A

$10 Ω$
B

$20 Ω$
C

$30 Ω$
D

$40 Ω$

Solution

$\begin{array}{l} \frac{i}{i_{g}} = 1 + \frac{G}{S} \\ \Rightarrow \frac{i . G}{V_{g}} = 1 + \frac{G}{S} \Rightarrow \frac{100 \times 10^{- 3} \times 40}{800 \times 10^{- 3}} = 1 + \frac{40}{S} \\ \Rightarrow S = 10 Ω \end{array}$

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