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To convert a 800 mV range milli voltmeter of resistance 40  Ω into a galvanometer of 100 mA range, the resistance to be connected as shunt is

a
10  Ω
b
20  Ω
c
30  Ω
d
40  Ω

detailed solution

Correct option is A

iig =1+GS⇒    i.GVg =1+GS  ⇒  100 ×  10−3  ×  40800 ×  10−3 =1+40S⇒   S=10   Ω

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