First slide

The lens

Question

A convex lens of focal length 0.5 m and concave lens of focal length 1 m are combined. The power of the resulting lens will be

Moderate

A

1 D
B

– 1 D
C

0.5 D
D

– 0.5 D

Solution

$P = P_{1} + P_{2} = \frac{1}{f_{1}} + \frac{1}{f_{2}} = \frac{1}{(0 .5)} + \frac{1}{(- 1)} = 1 D$

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