The co-ordinates of a moving particle in X-Y plane at any time t are given by x = ct2 and y = bt2. The speed of the particle at a time ‘t’ is given by:
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a
2t c + b
b
2tc2−b2
c
tc2+b2
d
2tc2+b2
answer is D.
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Detailed Solution
given x=ct2differentiate with respect to timedxdt=2ct=VXy=bt2differentiate with respect to timedydt=2bt=VY∴v=vx2+vy2 v=2tc2+b2