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A copper ball of mass m = 1 kg with a radius of r = 10 cm rotates with angular velocity ω = 2 rad/s about an axis passing through its centre. The work should be performed to increase the angular velocity of rotation of the ball two fold is

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a

1.2 × 10-2 J

b

2.4 × 10-2 J

c

3.6 × 10-2 J

d

4.8 × 10-2 J

answer is B.

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Detailed Solution

K.E. = 12Iω2If ω is to be doubledTherefore,W= ∆K.E. = K.E.2-K.E.1 = 12I[ω22 -ω1 2] ∆ K.E. = 12 25mr2[ω22-ω21] = 210×1[(110)2][42-22] =2.4 ×10-2 J

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