A copper block of mass 2.5 kg is heated in a furnace to a temperature of 5000C  and then placed on a large ice block. What is the maximum amount (approx.) of ice that can melt? (Specific heat of copper = 0.39 J/g0C latent heat of fusion of ice = 335 J/g)

Here, mass of copper block,    M = 2.5 kg = 2.5× 103 gRise in temperature of the copper block,   ∆T = 5000C-00C = 5000CSpecific heat of copper. c = 0.39 J/g0CLatent heat of fusion of water, L = 335 J/gIf m is  the mass of ice melted, applying the principle of calorimetry,Heat gained by ice = heat lost by copper blocki.e., mL = Mc ∆Tor   m = Mc ∆TL           = 2.5×103(g)×0.39(J/gC0)×500(Co)335(J/g)            = 1455 g = 1.455 = 1.5 kg