A copper block of mass 2.5 kg is heated in a furnace to a temperature of ${500}^0\mathrm{C}$ and then placed on a large ice block. What is the maximum amount (approx.) of ice that can melt? (Specific heat of copper = 0.39 $\mathrm{J}/{\mathrm{g}}^0\mathrm{C} \mathrm{latent} \mathrm{heat} \mathrm{of} \mathrm{fusion} \mathrm{of} ice = 335 \mathrm{J}/\mathrm{g})$

detailed solution

Correct option is B

Here, mass of copper block,    M = 2.5 kg = 2.5× 103 gRise in temperature of the copper block,   ∆T = 5000C-00C = 5000CSpecific heat of copper. c = 0.39 J/g0CLatent heat of fusion of water, L = 335 J/gIf m is  the mass of ice melted, applying the principle of calorimetry,Heat gained by ice = heat lost by copper blocki.e., mL = Mc ∆Tor   m = Mc ∆TL           = 2.5×103(g)×0.39(J/gC0)×500(Co)335(J/g)            = 1455 g = 1.455 = 1.5 kg