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A copper disc of radius 0.1 m is rotated about its centre with 10 revolutions per second in a uniform magnetic field of 0.1 Tesla with its plane perpendicular to the field. The e.m.f. induced across the radius of disc is
detailed solution
Correct option is C
e=12Bωr2=12×0.1×2π×10×(0.1)2=π×10−2VTalk to our academic expert!
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A copper disc of radius 10 cm is rotating in magnetic field B = 0.4 gauss with 10 rev./sec. What will be potential difference across peripheral points of disc?
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