Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

A copper ring carrying a current is placed in a uniform magnetic field in such a way that the ring experiences maximum possible torque of 2 N-m. Now the ring is rotated through an angle of 60o about a diameter which is perpendicular to the field direction. In this position torque experienced by the ring will be

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

1 N-m

b

0.5 N-m

c

1.732 N-m

d

1.414 N-m

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

For the position shown in figure, torque experienced by the ring is maximum and ςmax⁡=MBsin⁡90o=MB when the ring is rotated through an angle of 60o about the diameter PQ, the angle between M→ and B→ is 30o∴ς=MBsin⁡30o=ςmax⁡×12=2×12N−m=1N−m
Watch 3-min video & get full concept clarity

courses

No courses found

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon