A copper rod AB of length l is made to move with constant velocity $\vec{v}$ in a uniform magnetic field of induction $\vec{B}$ as shown in the figure. Then

Moderate

A

end A will acquire positive polarity and end B will acquire negative polarity.
B

ends A and B of the rod will acquire positive polarity and mid point C will acquire negative polarity.
C

ends A and B of the rod will acquire negative polarity and mid point C will acquire positive polarity.
D

end A will acquire negative polarity and end B will acquire positive polarity.

Solution

Magnetic force on each free electron in the rod $\vec{F_{e}} = (- e) \vec{v} x \vec{B}$ which is directed from A to B. As a result free electrons will move towards end B. Hence end A becomes positively charged and end B becomes negatively charged.

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