A copper rod AB of length 2m is moving in a uniform magnetic field of 1.5 T with a velocity of 3 m/s. The induced potential difference between ends A and B is

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3.5 volt

4.5 volt

33 volt

932 volt

answer is D.

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Detailed Solution

VA-VB=V→ x B→. BA→=VBsin90oBAcos90o−θ=3×1.5×2sin60o volt=932volt

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