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Q.

A copper rod AB of length 1m is moving in a uniform magnetic field of induction 0.5Telsa with velocity v = 20 m/s. Then magnitude of electrostatic field at a point inside the rod is

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a

10 v/m

b

1 v/m

c

20 v/m

d

100 v/m

answer is A.

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Detailed Solution

E→=B→ x V→∴E=BVsin90o=0.5 x 20 m/s=10 v/m
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