A copper rod ABCD is bent in the form of a circular arc as shown in the figure and its two end are connected to the terminals of a battery. If drift velocity of free electrons at the edges AB and CD are V1 and V2 respectively, then
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
V1 = V2
b
V1 > V2
c
V1 < V2
d
sufficient information is not given to compare V1 with V2
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
consider two arc like elements, each of cross sectional area ∆A, near the edges AB and CD.Now Vd=jne=Eρ.l∆A.∆A.ne=Eρnel⇒Vd∝1lsince the arc length AB is greater than CD, we can conclude V1 < V2 .