Questions
A copper rod of length l is rotated about one end perpendicular to the magnetic field B with constant angular velocity . The induced e.m.f. between the two ends is
detailed solution
Correct option is A
If in time t. the rod turns by an angle θ, the area generated by the rotation of rod will be =12l×lθ So the flux linked with the area generated by the rotation of rodϕ=B12l2θcos0=12Bl2θ=12Bl2ωt And so e=dϕdt=ddt12Bl2ωt=12Bl2ωTalk to our academic expert!
Similar Questions
The diagram shows a circuit having a coil of resistance and inductance L connected to a conducting rod PQ which can slide on a perfectly conducting circular ring of radius 10 cm with its centre at 'P'. Assume that friction and gravity are absent and a constant uniform magnetic field of 5 T exists as shown in figure.
At t = 0, the circuit is switched on and simultaneously a time varying external torque is applied on the rod so that it rotates about P with a constant angular velocity 40 rad/s. Find magnitude of this torque (in milli Nm) when current reaches half of its maximum value. Neglect the self-inductance of the loop formed by the circuit.
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