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Q.

A copper wire and an aluminum wire have lengths in the ratio 3 : 2, diameters in the ratio 2 : 3 and forces applied in the ratio 4 : 5. Find the ratio of the increase in length of the two wires. (YCu=1.1×1011Nm−2,YAl=0.70×1011Nm−2)

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a

110:189

b

180:110

c

189:110

d

80:11

answer is C.

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Detailed Solution

Y=Fℓπr2e⇒e=Fℓπr2Y ⇒e1e2=F1F2×l1l2×r2r12×Y2Y1 ⇒e1e2=45×32×322×0.7×10111.1×1011=189110
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