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Q.

A copper wire (Y = 1011 Nm-2) of length 8 m and steel wire (Y = 2×1011Nm-2) of length 4 m and each of cross-sectional area 0.5 cm2 are fastened end to end and stretched with a tension of 500 N. Match the given columns and select the correct option from the codes given below.Codes

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a

i-r, ii-p, iii-q

b

i-p, ii-q, iii-r

c

i-q, ii-r, iii-s

d

i-p, ii-s, iii-p

answer is A.

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Detailed Solution

∆lcopper = FlAY = 500×80.5×10-4×1011 = 0.8 mm∆lsteel = FlAY = 500×40.5×10-4×2×1011 = 0.2 mm(∆l)net = ∆lcopper+∆lsteel = 0.8+0.2 = 1.0 mm

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