Q.
A cord is used to lower vertically a block of mass M by a distance d with constant downward acceleration g4. Work done by the cord on the block is
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a
Mgd4
b
3Mgd4
c
−3Mgd4
d
Mgd
answer is C.
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Detailed Solution
When the block moves vertically downward with acceleration g4 then tension in the cordT=Mg−g4 =34MgWork done by the cord = F→.s→=Fscosθ=Tdcos(180°)=−3Mg4×d=−34Mgd
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