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Q.

A cord is used to lower vertically a block of mass M by a distance d with constant downward acceleration g4. Work done by the cord on the block is

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a

Mgd4

b

3Mgd4

c

−3Mgd4

d

Mgd

answer is C.

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Detailed Solution

When the block moves vertically downward with acceleration g4 then tension in the cordT=Mg−g4 =34MgWork done by the cord = F→.s→=Fscosθ=Tdcos(180°)=−3Mg4×d=−34Mgd
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