Q.

A cord is wound around the circumference of a bicycle wheel (without tyre) of diameter 1 m. A mass of 2 kg is tied to the end of the cord and it is allowed to fall from rest. The weight falls 2m in 4 s. The axle of the wheel is horizontal and the wheel rotates with its plane vertical. (Take g=10ms−2 ) then the angular acceleration of the wheel is (rad/s2)

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answer is 0.5.

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Detailed Solution

We first find the linear acceleration a by using the relation     s=ut+12at22=0+12×a×(4)2which gives a=14ms−2. Now R = 0.5 m. The angular acceleration α isα=aR=14×0.5=12=0.5rads−2.
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