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Graphical representation-Motion in 1 d

Question

 Corresponding to velocity-time graph in one dimensional motion of a particle as shown in } \ figure, match the following two columns.
 

Column IColumn II
(a) Average velocity between zero second and 4 s(p) 10  SI units
(b) Average acceleration between  1 s and 4 s(q) 2.5 SI units
(c) Average speed between zero second and 6 s(r) 5 SI units
(d) Rate of change of speed at } 4 s(s) None of the above

 

Moderate
Solution

(a) Average velocity =St= Area of v-t graph  Time  =204=5 m/s
(b) Average acceleration =vf-vi time  =v4s-v14-1=0-53=-53 m/s2

(c) Average speed 
=dt= Total area  Time  =20+106=5 m/s
(d) Rate of change of speed at 4 s=|a|

=slope of v-t graph = 5m/s2 



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