Corresponding to velocity-time graph in one dimensional motion of a particle as shown in } \ figure, match the following two columns.

(a) Average velocity =St= Area of v-t graph  Time  =204=5 m/s(b) Average acceleration =vf-vi time  =v4s-v14-1=0-53=-53 m/s2(c) Average speed =dt=∣ Total area ∣ Time  =20+106=5 m/s(d) Rate of change of speed at 4 s=|a|=∣slope of v-t graph∣ = 5m/s2